Answer
$12\sqrt5$
Work Step by Step
If a triangle has sides $a,b,c$, its perimeter is $a+b+c$.
Hence here: $P=\sqrt{45}+\sqrt{80}+\sqrt{125}=\sqrt9\sqrt5+\sqrt{16}\sqrt5+\sqrt{25}\sqrt5=3\sqrt5+4\sqrt5+5\sqrt5=12\sqrt5$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set - Page 539: 83
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