Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set: 46

Answer

$2\sqrt{5}$

Work Step by Step

RECALL: The quotient rule: $\dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}=\sqrt[n]{\dfrac{a}{b}}$ where $\sqrt[n]{a}$ and $\sqrt[n]{b}$ are real numbers and $b\ne0$ Use the rule above to obtain: $=\sqrt{\dfrac{200}{10}} \\=\sqrt{20}$ Factor the radicand so that at least one factor is a perfect square then simplify to obtain: $=\sqrt{4(5)} \\=\sqrt{2^2(5)} \\=2\sqrt{5}$
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