Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set - Page 539: 63

Answer

$\sqrt[3] {x+3}$.

Work Step by Step

The given expression is $\frac{\sqrt[3] {x^2+5x+6}}{\sqrt[3] {x+2}}$ Use the quotient rule $\frac{\sqrt[n] a}{\sqrt[n] b} = \sqrt[n] {\frac{a}{b}}$. $=\sqrt[3] {\frac{x^2+5x+6}{x+2}}$ Factor the numerator. $=\sqrt[3] {\frac{x^2+3x+2x+6}{x+2}}$ $=\sqrt[3] {\frac{x(x+3)+2(x+3)}{x+2}}$ $=\sqrt[3] {\frac{(x+3)(x+2)}{x+2}}$ Cancel out common terms. $=\sqrt[3] {x+3}$.
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