Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set: 7

Answer

$\sqrt{13} + 2\sqrt{5}$

Work Step by Step

Regroup the terms to obtain: $=(3\sqrt{13}-2\sqrt{13})+(4\sqrt{5}-2\sqrt{5})$ RECALL: The distributive property states that for any real numbers a, b, and c: (1) $ac + bc = (a+b)c$ (2) $ac - bc = (a-b)c$ Use rule (1) above to combine like terms: $=(3-2)\sqrt{13} + (4-2)\sqrt{5} \\=1\sqrt{13} + 2\sqrt{5} \\=\sqrt{13} + 2\sqrt{5}$
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