Answer
$\dfrac{2x\sqrt{2x}}{5y^3}$
Work Step by Step
RECALL:
The quotient rule:
$\sqrt[n]{\dfrac{a}{b}}=\dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}$
where
$\sqrt[n]{a}$ and $\sqrt[n]{b}$ are real numbers and $b\ne0$
Use the quotient rule above to obtain:
$=\dfrac{\sqrt{8x^3}}{\sqrt{25y^{6}}}
\\=\dfrac{\sqrt{4x^2(2x)}}{\sqrt{(5y^3)^2}}
\\=\dfrac{\sqrt{(2x)^2(2x)}}{5y^3}
\\=\dfrac{2x\sqrt{2x}}{5y^3}$
