## Intermediate Algebra for College Students (7th Edition)

$11\sqrt{5x}$
Simplify each radical to obtain: $=5\sqrt{9(5x)} - 2\sqrt{4(5x)} \\=5\sqrt{3^2(5x)} - 2\sqrt{2^2(5x)} \\=5(3)\sqrt{5x}- 2(2)\sqrt{5x} \\=15\sqrt{5x} - 4\sqrt{5x}$ RECALL: The distributive property states that for any real numbers a, b, and c: (1) $ac + bc = (a+b)c$ (2) $ac-bc=(a-b)c$ Use rule (2) above to combine like terms and obtain: $=(15-4)\sqrt{5x} \\=11\sqrt{5x}$