Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set: 18

Answer

$9\sqrt[3]{3}$

Work Step by Step

Simplify each radical to obtain: $=3\sqrt[3]{8(3)} + \sqrt[3]{27(3)} \\=3\sqrt[3]{2^3(3)} + \sqrt[3]{3^3(3)} \\=3(2)\sqrt[3]{3} + 3\sqrt[3]{3} \\=6\sqrt[3]{3} + 3\sqrt[3]{3}$ RECALL: The distributive property states that for any real numbers a, b, and c: (1) $ac + bc = (a+b)c$ (2) $ac-bc=(a-b)c$ Use the rule (1) above to combine like terms and obtain: $=(6+3)\sqrt[3]{3} \\=9\sqrt[3]{3}$
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