Answer
$9\sqrt[3]{3}$
Work Step by Step
Simplify each radical to obtain:
$=3\sqrt[3]{8(3)} + \sqrt[3]{27(3)}
\\=3\sqrt[3]{2^3(3)} + \sqrt[3]{3^3(3)}
\\=3(2)\sqrt[3]{3} + 3\sqrt[3]{3}
\\=6\sqrt[3]{3} + 3\sqrt[3]{3}$
RECALL:
The distributive property states that for any real numbers a, b, and c:
(1) $ac + bc = (a+b)c$
(2) $ac-bc=(a-b)c$
Use the rule (1) above to combine like terms and obtain:
$=(6+3)\sqrt[3]{3}
\\=9\sqrt[3]{3}$
