Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 533: 124

Answer

$\dfrac{|y| \sqrt[4] {7y}}{|x^3|}$

Work Step by Step

Simplify. $\dfrac{\sqrt[4] {7y^5}}{\sqrt [4] {x^{12}}}$ Now, $\dfrac{\sqrt[4] {7y^5}}{\sqrt [4] {x^{12}}}=\dfrac{\sqrt[4] {7y \cdot y^4}}{\sqrt [4] {(x^3)^{4}}}$ Thus, in the absolute sign,we have $=\dfrac{|y| \sqrt[4] {7y}}{|x^3|}$
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