Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 533: 112



Work Step by Step

Since, $\sqrt{ab}=\sqrt a \sqrt b$ Thus, $\sqrt[n]{ab}=\sqrt[n] a \sqrt[n] b$ Here, $n$ refers as index. If two radicals will have have same index then their product will also have same index. such as: Since, $ \sqrt[3] 4 \cdot \sqrt[3] 4=\sqrt[3]{4 \cdot 4}=\sqrt [3]{16} \ne 4$ Hence, the statement false.
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