Answer
False
Work Step by Step
Since, $\sqrt{ab}=\sqrt a \sqrt b$
Thus, $\sqrt[n]{ab}=\sqrt[n] a \sqrt[n] b$
Here, $n$ refers as index.
If two radicals will have have same index then their product will also have same index.
such as: Since, $ \sqrt[3] 4 \cdot \sqrt[3] 4=\sqrt[3]{4 \cdot 4}=\sqrt [3]{16} \ne 4$
Hence, the statement false.
