Answer
False
Work Step by Step
Since, $\sqrt{ab}=\sqrt a \sqrt b$
Thus,
$\sqrt {12} = \sqrt {4 \cdot 3}=\sqrt 4 \cdot \sqrt 3 =2 \sqrt 3$
Hence, the statement false.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 533: 113
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