# Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 533: 113

False

#### Work Step by Step

Since, $\sqrt{ab}=\sqrt a \sqrt b$ Thus, $\sqrt {12} = \sqrt {4 \cdot 3}=\sqrt 4 \cdot \sqrt 3 =2 \sqrt 3$ Hence, the statement false.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.