Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 533: 120

Answer

$(2,-4)$

Work Step by Step

we have two equations, such as: $-15x-6y=-6$ and $8x+6y=-8$ Now, add both the equations, we have $x=2$ Plugging the value of $x=2$ in one of the equation to get the value of $y$. Thus, $-15(2)-6y=-6$ or, $-30-6y=-6$ or, $5+y=1$ or, $y=1-5=-4$ Hence, $(x,y)=(2,-4)$
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