Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 578: 95



Work Step by Step

Solve.$(7+8i)(7-8i)$ Need to drop the parentheses and multiply the terms and apply the formula of sum of two multiples such as: $(a+b)(a-b)=a^2-b^2$ $=(7)^2-(8i)^2$ Since, $i^2=-1$ Thus, $=49-64(-1)$ or,$=49+64$ or, $=113$
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