## Intermediate Algebra for College Students (7th Edition)

$-12-8i$ or, $-12(12+8i)$
Solve.$4i(3i-2)$ or, $=(4i)(3i)-(4i)(2)$ Need to drop the parentheses and change the sign in context of the sign presence outside the bracket. we have, $=12i^2-8i$ Since, $i^2=-1$ Thus, $=-12-8i$ or, $=-12(12+8i)$