Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 578: 92


$-12-8i$ or, $-12(12+8i)$

Work Step by Step

Solve.$4i(3i-2)$ or, $=(4i)(3i)-(4i)(2)$ Need to drop the parentheses and change the sign in context of the sign presence outside the bracket. we have, $=12i^2-8i$ Since, $i^2=-1$ Thus, $=-12-8i$ or, $=-12(12+8i)$
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