Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 578: 94

Answer

$=-7-24i$.

Work Step by Step

The given expression is $=(3-4i)^2$ Use the special formula $(A-B)^2=A^2-2AB+B^2$. We have $A=3$ and $B=4i$. $=(3)^2-2(3)(4i)+(4i)^2$ Simplify. $=9-24i+16i^2$ Use $i^2=-1$. $=9-24i+16(-1)$ Simplify. $=9-24i-16$ $=-7-24i$.
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