Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Review Exercises - Page 578: 89

Answer

$-2i\sqrt 2$

Work Step by Step

Solve $-\sqrt{-8}$ As per square root property, we have $\sqrt{8}=\sqrt{2 \cdot 2 \cdot 2}=\sqrt{2^2} \cdot \sqrt 2= 2\sqrt 2$ Thus, $-\sqrt{-8}=-2\sqrt 2\sqrt {-1}$ Since, $i^2=-1$ and $\sqrt {-1}=i$ Hence, $-\sqrt{-8}=-2i\sqrt 2$
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