Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.7 - Formulas and Applications of Rational Equations - Exercise Set - Page 478: 83

Answer

$8$.

Work Step by Step

The given equation is $\Rightarrow S=\frac{kA}{P}$ Substitute $A=60,000,P=40$ and $S=12,000$. $\Rightarrow 12,000=\frac{k60,000}{40}$ Simplify. $\Rightarrow 12,000=1,500k$ Divide both sides by $1,500$. $\Rightarrow \frac{12,000}{1,500}=\frac{1,500k}{1,500}$ Simplify. $\Rightarrow 8=k$ Hence, the value of $k$ is $8$.
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