Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.7 - Formulas and Applications of Rational Equations - Exercise Set - Page 478: 72

Answer

false.

Work Step by Step

The given expression is $qf+pf=pq$. Subtract $qf+pq$ from both sides. $\Rightarrow qf+pf-(qf+pq)=pq-(qf+pq)$ Simplify. $\Rightarrow qf+pf-qf-pq=pq-qf-pq$ $\Rightarrow pf-pq=-qf$ Factor out $p$ from the left hand side. $\Rightarrow p(f-q)=-qf$ Divide both sides by $(f-q)$. $\Rightarrow \frac{p(f-q)}{(f-q)}=\frac{-qf}{(f-q)}$ Simplify. $\Rightarrow p=\frac{-qf}{f-q}$ Hence, the given statement is false.
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