Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.7 - Formulas and Applications of Rational Equations - Exercise Set - Page 478: 81

Answer

(a.) $k=16$. (b.) $y=16x^2$. (c.) $y=400$.

Work Step by Step

$\Rightarrow y=kx^2$ Substitute $x=2$ and $y=64$. $\Rightarrow 64=k(2)^2$ Simplify. $\Rightarrow 64=4k$ Divide both sides by $4$. $\Rightarrow \frac{64}{4}=\frac{4k}{4}$ Simplify. $\Rightarrow 16=k$ Hence, the value of $k$ is $16$. (b.) Substitute $k=16$ into the equation. $\Rightarrow y=16x^2$. Hence, the resulting equation is $y=16(5)^2$. (c.) Substitute $x=5$ into the equation from part (b.). $\Rightarrow y=16(5)^2$. Simplify. $\Rightarrow y=16\cdot25$. $\Rightarrow y=400$. Hence, the value of $y$ is $400$.
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