Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.7 - Formulas and Applications of Rational Equations - Exercise Set - Page 478: 82

Answer

(a.) $k=96$. (b.) $y=\frac{96}{x}$. (c.) $y=32$.

Work Step by Step

$\Rightarrow y=\frac{k}{x}$ Substitute $x=8$ and $y=12$. $\Rightarrow 12=\frac{k}{8}$ Multiply both sides by $8$. $\Rightarrow 8\cdot12=8\cdot \left (\frac{k}{8}\right )$ Simplify. $\Rightarrow 96=k$ Hence, the value of $k$ is $96$. (b.) Substitute $k=96$ into the equation. $\Rightarrow y=\frac{96}{x}$ Hence, the resulting equation is $y=\frac{96}{x}$. (c.) Substitute $x=3$ into the equation from part (b.). $\Rightarrow y=\frac{96}{3}$ Simplify. $\Rightarrow y=32$ Hence, the value of $y$ is $32$.
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