Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.3 - Greatest Common Factors and Factoring by Grouping - Exercise Set - Page 349: 114

Answer

$2$.

Work Step by Step

The given expression is $(x-?)(x-12)=x^2-14x+24$ Factor the right hand side of the equation. $=x^2-14x+24$ $=x^2-12x-2x+24$ $=x(x-12)-2(x-12)$ $=(x-2)(x-12)$ Plug into the given expression. $(x-?)(x-12)=(x-2)(x-12)$ By comparing both sides, the question mark is $2$.
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