Answer
$4y^{2n}\cdot(2y^4+4y^3-3)$
Work Step by Step
$8y^{2n+4}+16y^{2n+3}-12y^{2n}=\\=4y^{2n}\cdot2y^4+4y^{2n}\cdot4y^3+4y^{2n}\cdot(-3)\\=4y^{2n}\cdot(2y^4+4y^3-3)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Section 5.3 - Greatest Common Factors and Factoring by Grouping - Exercise Set - Page 349: 107
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