Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.3 - Greatest Common Factors and Factoring by Grouping - Exercise Set - Page 349: 106

Answer

$3x^{2m}y^{m}( x^m- 2y^{m})$

Work Step by Step

$3x^{3m}y^{m}-6x^{2m}y^{2m}=\\=3x^{2m}y^{m}\cdot x^m+3x^{2m}y^{m}\cdot (-2y^m)\\=3x^{2m}y^{m}( x^m- 2y^{m})$
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