Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.3 - Greatest Common Factors and Factoring by Grouping - Exercise Set - Page 347: 62

Answer

$(x+2)(2x^2-5)$

Work Step by Step

$2x^3-10+4x^2-5x=\\=2x^3+4x^2-5x-10\\=2x^2(x+2)-5(x+2)\\=(x+2)(2x^2-5)$
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