Answer
$3x^2y^4(5xy^2-3x^2+4y)$
Work Step by Step
The GCF of the two terms is $3x^2y^4$.
So $15x^3y^6-9x^4y^4+12x^2y^5=3x^2y^4\cdot5xy^2-3x^2y^4\cdot(-3x^2)+3x^2y^4\cdot4y=3x^2y^4(5xy^2-3x^2+4y)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Section 5.3 - Greatest Common Factors and Factoring by Grouping - Exercise Set - Page 347: 17
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