#### Answer

$(x+3)(2x+1)$

#### Work Step by Step

The $GCF$ for the two terms is a binomial, $(x+3)$. Even though it is a binomial, we can factor it out just like we would factor out a number or a variable. Thus, we factor out the binomial to obtain:
$=(x+3)[(x+2) + (x-1)]
\\=(x+3)(x+2+x-1)
\\=(x+3)(2x+1)$