Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.3 - Greatest Common Factors and Factoring by Grouping - Exercise Set - Page 347: 48



Work Step by Step

Regroup the terms to obtain: $=(x^2+3x)+(-5x-15)$ Factor out the greatest common factor of each group to obtain: $=x(x+3) + (-5)(x+3)$ The $GCF$ for the two terms is a binomial, $(x+3)$. Even though it is a binomial, we can factor it out just like we would factor out a number or a variable. Thus, we factor out the binomial to obtain: $=(x+3)[x+(-5)] \\=(x+3)(x-5)$
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