Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.5 - Linear Programming - Review Exercises - Page 309: 25

Answer

The solution set is $\{-4,3\}$.

Work Step by Step

The given equation is $\left | 2x+1 \right |=7$ Remove absolute value bars. $2x+1=-7$ or $ 2x+1 =7$ Substract $1$ from both sides. $2x+1-1=-7-1$ or $ 2x+1 -1=7-1$ Simplify. $2x=-8$ or $ 2x=6$ Divide both sides by $2$. $\frac{2x}{2}=-\frac{8}{2}$ or $ \frac{2x}{2}=\frac{6}{2}$ Simplify. $x=-4$ or $ x=3$.
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