Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.5 - Linear Programming - Review Exercises - Page 309: 15

Answer

$(6,8)$. The solution set graph is shown below.

Work Step by Step

The given compound inequality is $\Rightarrow -2x\lt-12$ and $x-3\lt5$. First $\Rightarrow -2x\lt-12$ Divide both sides by $-2$ and change the sense of the inequality.. $\Rightarrow \frac{-2x}{-2}\lt\frac{-12}{-2}$ Simplify. $\Rightarrow x\gt6$ Second $\Rightarrow x-3\lt5$ Add $3$ to both sides. $\Rightarrow x-3+3\lt5+3$ Simplify. $\Rightarrow x\lt8$ First graph then take the intersection of the solution sets of the two inequalities. We can write the compound inequality. $x\lt 8$ as $(-\infty,8)$ and $x\gt 6$ as $(6,\infty)$ The union is $(-\infty,8)\cup(6,\infty)=(6,8)$. The graph is shown below.
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