Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.5 - Linear Programming - Review Exercises - Page 309: 20

Answer

$(-\infty,-2)$. The graph of the solution set is shown below.

Work Step by Step

The given compound inequality is $\Rightarrow 5x-2\leq-22$ or $-3x-2\gt4$. First $\Rightarrow 5x-2\leq-22$ Add $2$ to both sides. $\Rightarrow 5x-2+2\leq-22+2$ Simplify. $\Rightarrow 5x\leq-20$ Divide both sides by $5$. $\Rightarrow \frac{5x}{5}\leq\frac{-20}{5}$ Simplify. $\Rightarrow x\leq-4$ Second $\Rightarrow -3x-2\gt4$ Add $2$ to both sides. $\Rightarrow -3x-2+2\gt4+2$ Simplify. $\Rightarrow -3x\gt6$ Divide both sides by $-3$ and change the sense of the inequality.. $\Rightarrow \frac{-3x}{-3}\lt\frac{6}{-3}$ Simplify. $\Rightarrow x\lt-2$ First graph then take the union of the solution sets of the two inequalities. We can write the compound inequality. $x\leq-4$ as $(-\infty,-4]$ or $x\lt -2$ as $(-\infty,-2)$ The union is $(-\infty,-4]\cup(-\infty,-2)=(-\infty,-2)$. The graph is shown below.
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