Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.5 - Determinants and Cramer’s Rule - Exercise Set - Page 240: 9

Answer

$-\dfrac{7}{16}$

Work Step by Step

General formula to calculate the determinate of a matrix is: $D=\begin{vmatrix}p&q\\r&s\end{vmatrix}=ps-qr$ As per question, we have Thus, $D=\begin{vmatrix}\frac{1}{2}&\frac{1}{2}\\\frac{1}{8}&\frac{-3}{4}\end{vmatrix}$ or, $D=\dfrac{-3}{8}-\dfrac{1}{16}=-\dfrac{7}{16}$
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