Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.5 - Determinants and Cramer’s Rule - Exercise Set - Page 240: 41

Answer

$-42$

Work Step by Step

Since, we have $D=\begin{vmatrix}\begin{vmatrix}3&1\\-2&3\end{vmatrix}\begin{vmatrix}7&0\\1&5\end{vmatrix}\\\begin{vmatrix}3&0\\0&7\end{vmatrix}\begin{vmatrix}9&-6\\3&5\end{vmatrix}\end{vmatrix}$ or, $=\begin{vmatrix}9+2&35-0\\21-0&45+18\end{vmatrix}$; or, $=\begin{vmatrix}11&35\\21&63\end{vmatrix}$; or, $=-42$
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