Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.5 - Determinants and Cramer’s Rule - Exercise Set - Page 240: 19

Answer

$(x,y)=(4,2)$; dependent equation

Work Step by Step

Need to apply Cramer's Rule. $x=\dfrac{D_x}{D}$; $y=\dfrac{D_y}{D}$ Now, $D=\begin{vmatrix}3&-4\\2&2\end{vmatrix}=6+8=14$; $D_x=\begin{vmatrix}4&-4\\12&2\end{vmatrix}=8+48=56$; $D_y=\begin{vmatrix}3&4\\2&12\end{vmatrix}=36-8=28$ Thus, $x=\dfrac{56}{14}=4$ and $y=\dfrac{28}{14}=2$ Hence, $(x,y)=(4,2)$; dependent equation
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