Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.5 - Determinants and Cramer’s Rule - Exercise Set - Page 240: 8

Answer

$2$

Work Step by Step

General formula to calculate the determinate of a matrix is: $D=\begin{vmatrix}p&q\\r&s\end{vmatrix}=ps-qr$ As per question, we have Thus, $D=\begin{vmatrix}\frac{1}{5}&\frac{1}{6}\\-6&5\end{vmatrix}$ or, $D=\dfrac{1}{5}(5)-\dfrac{1}{6}(-6)=1+1=2$
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