Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.5 - The Point-Slope Form of the Equation of a Line - Exercise Set - Page 164: 62

Answer

$f(x)=-\frac{1}{4}x-6$.

Work Step by Step

The given perpendicular line equation is $\Rightarrow 4x-y=6$ The slope-intercept form is $\Rightarrow y=4x-6$ Slope of the above line is $m_1=4$ and $y-$intercept is $-6$ Two lines are perpendicular if their slopes are negative reciprocal to each other. Hence, slope of the perpendicular line $\Rightarrow m_2=−\frac{1}{m_1}$ $\Rightarrow m_2=−\frac{1}{4}$ $y-$ intercept is same for both lines Hence, the $y-$ intercept for the required line is $-6$. The standard slope-intercept form is $\Rightarrow y=mx+c$ Plug all values. $\Rightarrow y=(-\frac{1}{4})x-6$ Plug $y=f(x)$. $\Rightarrow f(x)=-\frac{1}{4}x-6$.
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