## Intermediate Algebra for College Students (7th Edition)

$y+7=-5(x+2) \qquad$ ... point-slope form $y=-5x-17 \qquad$ ... slope-intercept form
$y=-5x+4$ is in slope-intercept form. Its slope is $m=-5.$ A line parallel to it has the same slope, $m=-5$ and passes through $(x_{1},y_{1})=(-2,-7)$ We write the point-slope equation: $y-y_{1}=m(x-x_{1})$ $y+7=-5(x+2) \qquad$ ... point-slope form Simplify to slope-intercept form (solve for y) $y+7=-5x-10 \qquad$ ...add $(-7)$ $y=-5x-17 \qquad$ ... is the slope-intercept form