# Chapter 2 - Section 2.5 - The Point-Slope Form of the Equation of a Line - Exercise Set: 3

Point-slope form: $y-6=5(x+2)$ Function notation of the slope-intercept form: $f(x) = 5x+16$

#### Work Step by Step

RECALL: (i) The point-slope form of a line's equation is: $y-y_1=m(x-x_1)$ where m= slope and $(x_1, y_1)$ is a point on the line. (ii) The function notation of the slope-intercept form of a line's equation is: $f(x) = mx + b$ where m= slope and b = y-intercept The given line has m=5 and passes through the point (-2, 6). This means that the point-slope form of the line's equation is: $y-6 = 5[x-(-2)] \\y-6=5(x+2)$ Convert the equation to slope-intercept form by isolating $y$ to obtain: $y - 6 =5(x+2) \\y-6=5\cdot x + 5\cdot 2 \\y-6 =5x+10 \\y-6+6=5x+10+6 \\y=5x+16$ In function notation, the slope-intercept form of the equation is: $f(x) = 5x+16$

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