#### Answer

Point-slope form:
$y-5 = 3(x-2)$
Slope-intercept form in function notation:
$f(x)=3x-1$

#### Work Step by Step

RECALL:
(i) The point-slope form of a line's equation is:
$y-y_1=m(x-x_1)$
where
m= slope and $(x_1, y_1)$ is a point on the line.
(ii) Slope-intercept form in function notation has the equation:
$f(x) = mx + b$
where
m= slope and b = y-intercept
The given line has m=3 and passes through the point (2, 5). This means that the point-slope form of the line's equation is:
$y-5 = 3(x-2)$
Convert the equation to slope-intercept form by isolating $y$ to obtain:
$y -5=3\cdot x- 3 \cdot 2
\\y-5 = 3x-6
\\y-5+5 = 3x-6+5
\\y = 3x - 1$
In function notation, the equation is:
$f(x) = 3x - 1$