## Intermediate Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 2 - Section 2.5 - The Point-Slope Form of the Equation of a Line - Exercise Set - Page 163: 23

#### Answer

$y+5=0(x+2)$... point-slope form $y=-5 \qquad$ ... slope-intercept form $f(x)=-5$ $\qquad$ ... function notation

#### Work Step by Step

$(x_{1},y_{1})=(-2,-5) \; (x_{2},y_{2})=(3,-5)$ $m=\displaystyle \frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{-5-(-5)}{3-(-2)}=\frac{0}{5}=0$. So with $m=0$ and $(x_{1},y_{1})=(-2,-5)$, we write the point-slope form $y-y_{1}=m(x-x_{1})$ $y+5=0(x+2) \qquad$ ... point-slope form Simplify to slope-intercept form, $y=mx+b$ $y+5=0 \qquad$ ...add $(-8)$ $y=-5 \qquad$ ... is the slope-intercept form For function notation, replace $y$ with $f(x)$.

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