Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Mid-Chapter Check Point - Page 135: 21



Work Step by Step

$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}$ $f(-4)=(-4)^2-3(-4)+8=16+12+8=36$ $g(-4)=-2(-4)-5=8-5=3$ $(\frac{f}{g})(-4)=\frac{f(-4)}{g(-4)}=\frac{36}{3}=12$
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