Answer
$12$
Work Step by Step
$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}$
$f(-4)=(-4)^2-3(-4)+8=16+12+8=36$
$g(-4)=-2(-4)-5=8-5=3$
$(\frac{f}{g})(-4)=\frac{f(-4)}{g(-4)}=\frac{36}{3}=12$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 2 - Mid-Chapter Check Point - Page 135: 21
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