Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Mid-Chapter Check Point - Page 135: 16



Work Step by Step

$f(-1)=(-1)^2-(-1)\cdot3+8=1+3+8=12$ $g(3)=-2(3)-5=-6-5=-11$ Thus $f(-1)-g(3)=12-(-11)=23$
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