Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Mid-Chapter Check Point - Page 135: 17



Work Step by Step

$f(a)=a^2-3a+8$ $g(a+3)=-2(a+3)-5=-2a-6-5=-2a-11$ Thus $f(a)+g(a+3)=a^2-3a+8-2a-11=a^2-5a-3$
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