## Intermediate Algebra for College Students (7th Edition)

$(f+g)(x)=f(x)+g(x)$ $(f+g)(x)=f(x)+g(x)=x^2-3x+8-2x-5=x^2-5x+3$ Plug in $x=-2$ into $(f+g)(x)$: $(f+g)(-2)=(-2)^2-5(-2)+3=4+10+3=17$