Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Cumulative Review Exercises - Page 176: 12

Answer

$\frac{x^{10}}{y^{12}}$

Work Step by Step

First step is parentheses . Using the exponent properties $(x^n)^m=x^{n*m}$ $(\frac{3x^2*y^{-4}}{x^{-3}*y^2})^2=\frac{3x^{2*2}*y^{-4*2}}{x^{-3*2}*y^{2*2}}=\frac{3x^4*y^{-8}}{x^{-6}*y^4}$ Using $\frac{x^m}{x^n}=x^{m-n}$ $3x^{4-(-6)}*y^{-8-4}=3x^{10}*y^{-12}=\frac{x^{10}}{y^{12}}$
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