Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Cumulative Review Exercises - Page 176: 3

Answer

$7$

Work Step by Step

$\frac{8-3^2\div9}{|-5|-[5-(18\div6)]^2}\\=\frac{8-9\div9}{5-[5-3]^2}\\=\frac{8-1}{5-2^2}\\=\frac{7}{5-4}\\=\frac{7}{1}=7$
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