Answer
$\frac{y^{10}}{9x^8}$
Work Step by Step
$(3x^4y^{-5})^{-2}=3^{-2}(x^4)^{-2}(y^{-5})^{-2}=\frac{1}{9}x^{-8}y^{10}=\frac{y^{10}}{9x^8}$
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