Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Cumulative Review Exercises - Page 176: 11

Answer

$\frac{y^{10}}{9x^8}$

Work Step by Step

$(3x^4y^{-5})^{-2}=3^{-2}(x^4)^{-2}(y^{-5})^{-2}=\frac{1}{9}x^{-8}y^{10}=\frac{y^{10}}{9x^8}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.