Answer
$7,12,17,22$
Work Step by Step
Here, $a_1=7$
and $a_n=a_{n-1}+5$
For $n=2,3,4$ ,we have
$a_2=a_{2-1}+5=a_1+5=7+5=12$;
$a_3=a_{3-1}+5=a_2+5=12+5=17$;
$a_4=a_{4-1}+5=a_3+5=17+5=22$
Hence, the first four terms are: $7,12,17,22$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 831: 94
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