Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 831: 100

Answer

$-45$

Work Step by Step

Since,we have $4,-3,-10,....$ $a_n=a_1+(n-1)d$ Thus, $a_n=4+(n-1)(-7)$ and $a_8=4+(8-1)(-7)=4+7(-7)=4-49=-45$
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