Answer
$a_n=\dfrac{n+2}{n+1}$; $n=1,2,3,4,....$
Work Step by Step
Since, we have Since, we have $\dfrac{3}{2},\dfrac{4}{3},\dfrac{5}{4},\dfrac{6}{5}...$
or, $\dfrac{1+2}{1+1},\dfrac{2+2}{2+1},\dfrac{3+2}{3+1},\dfrac{4+2}{4+1}...$
The n-the term can be represented as:
$a_n=\dfrac{n+2}{n+1}$; $n=1,2,3,4,....$
