Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.1 - Sequences and Summation Notation - Exercise Set - Page 831: 78

Answer

False

Work Step by Step

since, we have $\sum_{i=1}^{2}a_ib_i=a_1b_1+a_2b_2$ and $\sum_{i=1}^{2}a_i\sum_{i=1}^{2}b_i=(a_1+a_2)(b_1+b_2)$ or, $=a_1b_1+a_2b_2+a_1b_2+a_2b_1$ or, $=\sum_{i=1}^{2}a_ib_i+a_1b_2+a_2b_1$ or,$\sum_{i=1}^{2}a_ib_i=\sum_{i=1}^{2}a_i\sum_{i=1}^{2}b_i-(a_1b_2+a_2b_1)$ Hence, the given statement is false.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.