Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Review Exercises - Page 818: 7

Answer

$(-2,-5).$

Work Step by Step

The vertex of $x=a(y-k)^2+h$ is at $(h,k)$. $x=y^2+10y+23\\x=x^2+10y+25-2\\x=(y+5)^2-2$ Thus here the vertex is at $(-2,-5).$
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